Kinetic Theory of Gases (Class 11 — ~20% weight)
Ideal gas equation, RMS speed, degrees of freedom, mean free path.
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Take a full mock →Q1 · Kinetic Theory of Gases (Class 11 — ~20% weight) · EASY
At a given temperature, the root mean square (rms) speed of oxygen molecules (O₂, molecular mass = 32 u) is 400 m/s. What will be the rms speed of hydrogen molecules (H₂, molecular mass = 2 u) at the same temperature?
Q2 · Kinetic Theory of Gases (Class 11 — ~20% weight) · MEDIUM
A monoatomic ideal gas and a diatomic ideal gas are at the same temperature. If the rms speed of molecules in the monoatomic gas is 500 m/s and both gases have the same molar mass, what is the rms speed of molecules in the diatomic gas?
Q3 · Kinetic Theory of Gases (Class 11 — ~20% weight) · HARD
At temperature T, the mean free path of molecules of a gas is λ. If the pressure is doubled and temperature is increased to 2T while keeping the volume constant, what will be the new mean free path?
Q4 · Kinetic Theory of Gases (Class 11 — ~20% weight) · MEDIUM
At what temperature will the RMS velocity of oxygen molecules be equal to that of hydrogen molecules at 27°C? (Molecular mass of O₂ = 32, H₂ = 2)
Q5 · Kinetic Theory of Gases (Class 11 — ~20% weight) · HARD
An ideal gas is enclosed in a container at 27°C. If the temperature is increased such that the root mean square velocity of the molecules becomes twice the initial value, the final temperature of the gas is: