JEE Main · Chemistry

Solutions

Different methods for expressing concentration of solution; vapour pressure of solutions and Raoult's law; ideal and non-ideal solutions; colligative properties — relative lowering of vapour pressure, elevation of boiling point, depression of freezing point, osmotic pressure; van't Hoff factor.

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  • Q1 · Solutions · EASY

    A solution is prepared by dissolving 18 g of glucose (molar mass = 180 g/mol) in 500 g of water. What is the molality of the solution?

  • Q2 · Solutions · MEDIUM

    The vapour pressure of pure water at 298 K is 23.8 mm Hg. A solution of 5 g of a non-volatile solute (molar mass = 50 g/mol) in 180 g of water has a vapour pressure of 23.5 mm Hg at the same temperature. What is the relative lowering of vapour pressure?

  • Q3 · Solutions · MEDIUM

    A 0.1 molal aqueous solution of a weak acid is 10% ionized. The freezing point depression of this solution is (Kf for water = 1.86 K kg mol⁻¹):

  • Q4 · Solutions · MEDIUM

    An aqueous solution containing 6.8 g of a non-volatile organic compound in 100 g of water has an osmotic pressure of 4.92 atm at 300 K. What is the molar mass of the compound? (R = 0.082 L atm K⁻¹ mol⁻¹, assume density of solution ≈ 1 g/mL)

  • Q5 · Solutions · HARD

    Two liquids A and B form an ideal solution. At 300 K, the vapour pressure of pure A is 400 mm Hg and that of pure B is 600 mm Hg. A solution is prepared by mixing 2 moles of A and 3 moles of B. What is the mole fraction of A in the vapour phase above the solution?

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