AP TET · Mathematics and Science (Paper II)

Area, surface area and volume of 2D and 3D figures.

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Mensuration

Area, Surface Area and Volume of 2D and 3D Figures

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Overview

Mensuration is the branch of mathematics dealing with measurement of geometric figures—their lengths, areas, and volumes. For AP TET Paper II, this topic carries significant weight as it tests both conceptual understanding and computational accuracy across classes 6-8 content.

Students must master two distinct domains: **2D figures** (calculating perimeter and area of plane shapes) and **3D figures** (calculating surface area and volume of solids). Questions typically involve direct formula application, word problems requiring identification of the correct shape, and comparison problems where students must relate different measurements.

The practical nature of mensuration makes it ideal for activity-based pedagogy questions. Expect problems linking real-life objects (water tanks, rooms, agricultural fields) to geometric calculations. A clear mental map of formulas and their logical derivations is essential—rote memorisation without understanding leads to frequent errors.

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Key Concepts

  • **Perimeter** is the total length of the boundary of a 2D figure; **Area** is the measure of the region enclosed within that boundary.
  • **Surface Area** of a 3D solid is the total area of all its outer faces—think of it as the amount of material needed to wrap the solid completely.
  • **Volume** measures the space occupied by a 3D object—the capacity it can hold. Volume is always expressed in cubic units (cm³, m³).
  • **Lateral Surface Area (LSA)** includes only the curved or side surfaces, excluding top and bottom faces. **Total Surface Area (TSA)** includes all faces.
  • For **composite figures**, break the shape into standard components, calculate separately, then add or subtract as needed.
  • Units matter critically: Area uses square units (cm², m²), Volume uses cubic units. Converting between units requires squaring or cubing the conversion factor.
  • **Relationship between dimensions**: If all dimensions of a figure are scaled by factor k, area scales by k² and volume scales by k³.

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Formulas / Key Facts

### 2D Figures

| Figure | Perimeter | Area | |--------|-----------|------| | Rectangle | 2(l + b) | l × b | | Square | 4a | a² | | Triangle | a + b + c | ½ × base × height | | Right Triangle | a + b + c | ½ × leg₁ × leg₂ | | Equilateral Triangle | 3a | (√3/4) × a² | | Parallelogram | 2(a + b) | base × height | | Rhombus | 4a | ½ × d₁ × d₂ | | Trapezium | Sum of all sides | ½ × (a + b) × h | | Circle | 2πr | πr² | | Semicircle | πr + 2r | ½πr² |

**Heron's Formula** for triangle with sides a, b, c:

  • s = (a + b + c)/2
  • Area = √[s(s-a)(s-b)(s-c)]

### 3D Figures

| Solid | Lateral/Curved SA | Total SA | Volume | |-------|-------------------|----------|--------| | Cuboid | 2h(l + b) | 2(lb + bh + hl) | l × b × h | | Cube | 4a² | 6a² | a³ | | Cylinder | 2πrh | 2πr(r + h) | πr²h | | Cone | πrl | πr(r + l) | ⅓πr²h | | Sphere | — | 4πr² | (4/3)πr³ | | Hemisphere | 2πr² | 3πr² | (2/3)πr³ |

**For cone**: Slant height l = √(r² + h²)

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Worked Examples

### Example 1: Area of Trapezium *A trapezium has parallel sides of 12 cm and 8 cm, and the perpendicular distance between them is 5 cm. Find its area.*

**Solution:**

  • Formula: Area = ½ × (sum of parallel sides) × height
  • Area = ½ × (12 + 8) × 5
  • Area = ½ × 20 × 5 = 50 cm²

### Example 2: Volume and Surface Area of Cylinder *A cylindrical water tank has radius 7 m and height 10 m. Find its volume and total surface area. (Use π = 22/7)*

**Solution:**

  • Volume = πr²h = (22/7) × 7² × 10 = (22/7) × 49 × 10 = 22 × 70 = 1540 m³
  • TSA = 2πr(r + h) = 2 × (22/7) × 7 × (7 + 10) = 2 × 22 × 17 = 748 m²

### Example 3: Composite Figure *A solid consists of a cone mounted on a hemisphere. Both have radius 3 cm. If the height of the cone is 4 cm, find the total surface area.*

**Solution:**

  • For cone: l = √(r² + h²) = √(9 + 16) = √25 = 5 cm
  • Curved SA of cone = πrl = π × 3 × 5 = 15π cm²
  • Curved SA of hemisphere = 2πr² = 2π × 9 = 18π cm²
  • Total SA = 15π + 18π = 33π cm² ≈ 103.71 cm²

(Note: The base of the cone sits on the hemisphere, so we don't add that circular area)

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Common Mistakes

  • **Confusing radius and diameter** → Always verify whether the problem gives radius (r) or diameter (d). If diameter is given, divide by 2 before applying formulas.
  • **Mixing up LSA and TSA** → Read carefully whether the question asks for "curved surface area" (LSA) or "total surface area" (TSA). A closed cylinder needs TSA; an open tank needs LSA + one base.
  • **Using wrong height in cones** → The formula uses perpendicular height (h) for volume but slant height (l) for curved surface area. Students often interchange these.
  • **Ignoring unit conversion** → If length is in metres and width in centimetres, convert to the same unit first. Area conversion: 1 m² = 10000 cm². Volume: 1 m³ = 1000000 cm³.
  • **Forgetting to add/subtract in composite figures** → When a cone is placed on a cylinder, the common circular face is internal—don't count it twice in surface area.
  • **Misapplying Heron's formula** → Students forget to calculate semi-perimeter (s) first or make arithmetic errors under the square root.

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Quick Reference

  • Rectangle area = l × b; Perimeter = 2(l + b)
  • Circle area = πr²; Circumference = 2πr
  • Cylinder volume = πr²h; TSA = 2πr(r + h)
  • Cone volume = ⅓πr²h; Slant height l = √(r² + h²)
  • Sphere volume = (4/3)πr³; Surface area = 4πr²
  • When dimensions scale by k: Area → k², Volume → k³

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A rectangular garden is 25 m long and 18 m wide. What is the area of the garden in square metres?

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  • Q1 · Mensuration · EASY

    A rectangular garden is 25 m long and 18 m wide. What is the area of the garden in square metres?

  • Q2 · Mensuration · MEDIUM

    A cylindrical water tank has a radius of 7 m and a height of 10 m. What is the volume of the tank in cubic metres? (Use π = 22/7)

  • Q3 · Mensuration · EASY

    The perimeter of a square field is 160 m. What is the area of the field?

  • Q4 · Mensuration · MEDIUM

    A cuboid has dimensions 12 cm (length), 8 cm (breadth), and 5 cm (height). What is the total surface area of the cuboid?

  • Q5 · Mensuration · HARD

    A cone has a base radius of 6 cm and a slant height of 10 cm. What is the curved surface area of the cone? (Use π = 3.14)

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Notes generated on 27 Jun 2026