Time and Distance — Study Notes for UP Police Constable
Overview
Time and Distance is one of the most frequently tested topics in the Numerical & Mental Ability section of UP Police Constable exam. Questions from this topic appear in almost every paper, typically 3–5 questions worth 10–15 marks. The topic tests your ability to apply the fundamental relationship between speed, distance and time in various real-world scenarios.
Mastery of this topic requires understanding the core formula (Distance = Speed × Time) and its applications in four main contexts: basic motion problems, train problems, boats and streams, and relative speed scenarios. These questions are highly formulaic — once you recognize the pattern, you can solve them in 30–60 seconds each. The key is practice and pattern recognition.
Most UP Police questions are straightforward calculations with minimal complexity. Focus on quick mental math, unit conversions (km/hr to m/s), and memorizing standard formulas for trains crossing platforms, relative speed, and upstream/downstream motion.
Key Concepts
**Basic relationship**: Distance = Speed × Time. Any two known quantities give you the third. Speed is measured in km/hr or m/s; always convert units when mixing them.
**Speed conversion**: To convert km/hr to m/s, multiply by 5/18. To convert m/s to km/hr, multiply by 18/5. This conversion appears in almost every train problem.
**Average speed**: When a person travels different distances at different speeds, average speed = Total Distance ÷ Total Time. **Never** calculate average speed as the arithmetic mean of two speeds unless distances are equal.
**Relative speed**: When two objects move in the same direction, relative speed = difference of speeds. When moving in opposite directions, relative speed = sum of speeds. This applies to trains passing each other and boats in streams.
**Trains**: A train must cover its own length plus any platform/bridge/pole length. Time to cross = (Train length + Object length) ÷ Speed. When two trains cross each other, consider sum of their lengths.
**Boats and streams**: Speed in still water (boat's own speed) combines with stream speed. Downstream speed = boat speed + stream speed. Upstream speed = boat speed − stream speed. Most problems give you upstream and downstream speeds to find boat and stream speeds.
**Meeting and overtaking**: Two objects starting from different points toward each other meet when sum of distances covered equals the total distance between them. When moving in the same direction, the faster overtakes when the difference in distances equals the initial gap.
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A train 120 metres long is running at a speed of 54 km/hr. How much time will it take to cross a pole?
Q2 · Time and Distance · MEDIUM
A boat travels 30 km upstream in 5 hours and the same distance downstream in 3 hours. What is the speed of the boat in still water?
Q3 · Time and Distance · MEDIUM
Two trains of lengths 150 metres and 200 metres are running in opposite directions at speeds of 45 km/hr and 54 km/hr respectively. In how much time will they cross each other?
Q4 · Time and Distance · HARD
A man travels from point A to point B at a speed of 40 km/hr and returns from B to A at a speed of 60 km/hr. If the entire journey takes 5 hours, what is the distance between A and B?
Q5 · Time and Distance · EASY
A train travels 180 km in 3 hours. What is its speed in km/hr?
**Example 1: Basic Time-Distance** A man travels 120 km at 40 km/hr and returns at 60 km/hr. Find his average speed for the entire journey.
**Solution**:
Total distance = 120 + 120 = 240 km
Time for onward journey = 120/40 = 3 hours
Time for return journey = 120/60 = 2 hours
Total time = 3 + 2 = 5 hours
Average speed = 240/5 = **48 km/hr**
(Note: Not (40+60)/2 = 50 km/hr — common mistake!)
**Example 2: Train Problem** A train 150 m long crosses a platform 250 m long in 20 seconds. Find the speed of the train in km/hr.
**Solution**:
Total distance to cover = 150 + 250 = 400 m
Time = 20 seconds
Speed = 400/20 = 20 m/s
Converting to km/hr: 20 × 18/5 = **72 km/hr**
**Example 3: Boats and Streams** A boat travels downstream at 15 km/hr and upstream at 9 km/hr. Find the speed of the boat in still water and the speed of the stream.
**Solution**:
Speed in still water = (15 + 9)/2 = 24/2 = **12 km/hr**
Stream speed = (15 − 9)/2 = 6/2 = **3 km/hr**
Common Mistakes
**Mistake 1**: Averaging speeds incorrectly → Adding two speeds and dividing by 2 when distances are different. **Fix**: Always use Average speed = Total Distance ÷ Total Time. Only use (s₁+s₂)/2 when told explicitly that distances are equal.
**Mistake 2**: Forgetting unit conversion → Mixing km/hr with m/s or train length in meters with speed in km/hr. **Fix**: Convert immediately at the start. Train problems almost always need m/s to km/hr conversion (multiply by 18/5) or vice versa (multiply by 5/18).
**Mistake 3**: Using wrong relative speed direction → Adding speeds when objects move in same direction or subtracting when opposite. **Fix**: Same direction = subtract speeds. Opposite direction = add speeds. Draw a quick diagram if confused.
**Mistake 4**: Ignoring train length in crossing problems → Using only platform/pole length. **Fix**: Total distance = Train length + Object length. When a train crosses a pole/person, object length is zero, so only train length counts.
**Mistake 5**: Confusing upstream and downstream → Mixing up which direction helps or hinders the boat. **Fix**: Downstream = WITH current (add stream speed). Upstream = AGAINST current (subtract stream speed). Remember "down = add, up = subtract."
Quick Reference
**D = S × T**: Master this and rearrange instantly for any unknown.
**km/hr to m/s**: multiply by 5/18; m/s to km/hr: multiply by 18/5.
**Average speed ≠ average of speeds** unless distances are equal.
**Relative speed**: Same direction → subtract; opposite direction → add.