RRB NTPC · Mathematics

Trains, boats and streams, relative speed, average speed.

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Time, Distance and Speed — Study Notes (RRB NTPC)

Overview

Time, Distance and Speed problems form a substantial portion of RRB NTPC Mathematics, typically contributing 4–6 questions directly, plus appearing in disguised forms in other topics like trains and boats. This topic tests your ability to translate real-world motion scenarios into mathematical relationships and solve for unknowns efficiently.

The core relationship **Distance = Speed × Time** is simple, but RRB questions demand quick application across trains crossing platforms, boats navigating streams, relative motion between two moving objects, and calculating average speeds over multi-leg journeys. Mastery requires fluency in unit conversions (km/h ↔ m/s), understanding relative speed concepts, and recognizing standard problem patterns within 60–90 seconds per question.

Strong performance here directly impacts your Mathematics score ceiling. Unlike abstract algebra, these are visualization-friendly problems — sketch the scenario, mark known quantities, and apply the right formula variant. Practice 40–50 problems across all sub-types to build pattern recognition and speed.

Key Concepts

  • **Fundamental relationship**: Distance = Speed × Time. Any problem ultimately reduces to this equation or a variant. Speed = Distance/Time, Time = Distance/Speed.
  • **Unit conversions are non-negotiable**: km/h to m/s multiply by 5/18; m/s to km/h multiply by 18/5. Many train problems give platform/train length in metres and speed in km/h.
  • **Relative speed — same direction**: When two objects move in the same direction, relative speed = |Speed₁ - Speed₂|. Used when one train overtakes another or a man walks inside a moving train.
  • **Relative speed — opposite direction**: When two objects move toward each other, relative speed = Speed₁ + Speed₂. Critical for head-on train collisions or crossing problems.
  • **Average speed ≠ arithmetic mean of speeds**: For a journey with multiple legs at different speeds, Average Speed = Total Distance / Total Time. Never just average the speeds unless distances are equal.
  • **Boats and streams logic**: Downstream speed = Boat speed in still water + Stream speed. Upstream speed = Boat speed in still water - Stream speed. Boat speed = (Downstream + Upstream)/2; Stream speed = (Downstream - Upstream)/2.
  • **Train crossing problems have two scenarios**: (a) Train crosses a stationary object (pole/man) — distance = train length; (b) Train crosses a platform/bridge — distance = train length + platform length.
  • **Time taken to cross when speeds are in opposite directions**: If two trains of lengths L₁ and L₂ move at speeds S₁ and S₂ toward each other, Time = (L₁ + L₂)/(S₁ + S₂).

Formulas / Key Facts

1. **Distance = Speed × Time** — The master equation. Rearrange as needed: S = D/T, T = D/S.

2. **km/h to m/s**: Multiply by 5/18. Example: 72 km/h = 72 × 5/18 = 20 m/s.

3. **m/s to km/h**: Multiply by 18/5. Example: 15 m/s = 15 × 18/5 = 54 km/h.

4. **Relative speed (same direction)**: S₁ - S₂ (assuming S₁ > S₂).

5. **Relative speed (opposite direction)**: S₁ + S₂.

6. **Average Speed**: Total Distance / Total Time (not the average of individual speeds).

7. **Downstream speed**: Speed in still water + Stream speed.

8. **Upstream speed**: Speed in still water - Stream speed.

9. **Speed in still water**: (Downstream speed + Upstream speed) / 2.

10. **Stream speed**: (Downstream speed - Upstream speed) / 2.

11. **Train crossing a pole**: Time = Length of train / Speed of train.

12. **Train crossing a platform**: Time = (Length of train + Length of platform) / Speed of train.

Worked Examples

**Example 1 (Basic Speed-Distance-Time):** A train covers 360 km in 4 hours. What is its speed in m/s?

*Solution:* Speed = Distance/Time = 360/4 = 90 km/h. Convert to m/s: 90 × 5/18 = 25 m/s.

**Example 2 (Relative Speed — Opposite Direction):** Two trains of lengths 120 m and 180 m run at 54 km/h and 72 km/h toward each other. How long do they take to cross each other completely?

*Solution:* Convert speeds: 54 km/h = 54 × 5/18 = 15 m/s; 72 km/h = 72 × 5/18 = 20 m/s. Relative speed = 15 + 20 = 35 m/s (opposite directions, so add). Total distance to cover = 120 + 180 = 300 m. Time = 300/35 = 60/7 seconds ≈ 8.57 seconds.

**Example 3 (Boats and Streams):** A boat travels 30 km downstream in 2 hours and returns upstream in 3 hours. Find the speed of the boat in still water and the stream speed.

*Solution:* Downstream speed = 30/2 = 15 km/h. Upstream speed = 30/3 = 10 km/h. Speed in still water = (15 + 10)/2 = 12.5 km/h. Stream speed = (15 - 10)/2 = 2.5 km/h.

**Example 4 (Average Speed):** A car travels 60 km at 30 km/h and the next 60 km at 60 km/h. What is the average speed?

*Solution:* Time for first leg: 60/30 = 2 hours. Time for second leg: 60/60 = 1 hour. Total distance = 60 + 60 = 120 km. Total time = 2 + 1 = 3 hours. Average speed = 120/3 = 40 km/h. (Note: Not 45 km/h, which would be the arithmetic mean of 30 and 60!)

Common Mistakes

  • **Averaging speeds directly**: Students calculate (30 + 60)/2 = 45 km/h for average speed, ignoring that time spent at each speed differs. → Always use Total Distance / Total Time.
  • **Forgetting unit conversion in train problems**: Platform length in metres, speed in km/h — students plug in directly without converting. → Convert km/h to m/s (× 5/18) before using metres in the formula.
  • **Adding speeds when trains move in the same direction**: When one train overtakes another, students add speeds instead of subtracting. → Same direction = subtract; opposite direction = add.
  • **Using only train length when crossing a platform**: Students forget to add platform length, using just train length as distance. → Distance = Train length + Platform/bridge length when crossing stationary structures.
  • **Mixing up downstream/upstream formulas**: Assigning downstream formula to upstream scenario. → Downstream = Boat + Stream; Upstream = Boat - Stream. The faster speed is always downstream.

Quick Reference

  • **Speed = Distance / Time**; memorize all three forms of this equation.
  • **km/h to m/s: × 5/18**; m/s to km/h: × 18/5.
  • **Relative speed (opposite): add speeds**; (same direction): subtract speeds.
  • **Average speed = Total Distance / Total Time**, never the arithmetic mean of speeds.
  • **Boat in still water = (Downstream + Upstream)/2**; Stream = (Downstream - Upstream)/2.
  • **Train crosses pole: Time = Train length / Speed**; crosses platform: add platform length to numerator.

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A train 150 metres long is running at a speed of 54 km/hr. How long will it take to cross a man standing on a platform?

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  • Q1 · Time, Distance and Speed · EASY

    A train 150 metres long is running at a speed of 54 km/hr. How long will it take to cross a man standing on a platform?

  • Q2 · Time, Distance and Speed · MEDIUM

    A boat can travel 20 km downstream in 2 hours and 12 km upstream in 3 hours. What is the speed of the boat in still water?

  • Q3 · Time, Distance and Speed · MEDIUM

    Two trains are running in opposite directions with speeds of 45 km/hr and 30 km/hr respectively. If the length of each train is 150 metres, how long will they take to cross each other?

  • Q4 · Time, Distance and Speed · MEDIUM

    A man travels from point A to point B at 40 km/hr and returns from B to A at 60 km/hr. What is his average speed for the entire journey?

  • Q5 · Time, Distance and Speed · HARD

    A 300 metre long train crosses a platform 600 metres long in 36 seconds. A man is running in the direction of the train at 10 km/hr. How long will the train take to overtake the man?

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Notes generated on 10 May 2026